JEE Main 11 Jan 2019 Shift 2 Solved Paper

Section: Mathematics
© examsiri.com
Question : 37 of 90
 
Marks: +1, -0
Let (x+10)50 + (x10)50 = a0+a1x+a2x2 + ... + a50x50 , for all x ∊ R , then
a2
a0
is equal to :
[11 Jan 2019 Shift 2]
Go to Question: