JEE Main 11 Jan 2019 Shift 2 Solved Paper

Section: Mathematics
© examsiri.com
Question : 35 of 90
 
Marks: +1, -0
area of the triangle whose one vertex is at the vertex of the parabola, y2 + 4(x – a2)= 0 and If the the other two vertices are the points of intersection of the parabola and y-axis, is 250 sq. units, then a value of 'a' is :-
[11 Jan 2019 Shift 2]
Go to Question: