Let α and β be the roots of the quadratic equation x^2 sin θ – x (sin θ cos θ + 1) + cos θ = 0 (0 < θ < 45°), and α < β. Then \sum^{\infty}_{n=0} (\alpha^n+(-1)^n/\beta^n) is equal to :- [11 Jan 2019 Shift 2]

Correct Answer is : 11−cosθ + 11+sinθ

1/{1-\cos\theta} + 1/{1+\sin\theta}

1/{1+\cos\theta} + 1/{1-\sin\theta}

1/{1-\cos\theta} - 1/{1+\sin\theta}

1/{1+\cos\theta} - 1/{1-\sin\theta}

JEE Main 11 Jan 2019 Shift 2 Solved Paper

Section: Mathematics

Question : 32 of 90

Marks: +1, -0

Let α and β be the roots of the quadratic equation x2 sin θ – x (sin θ cos θ + 1) + cos θ = 0 (0 < θ < 45°), and α < β. Then

∞

n=0

(αn+

(−1)n

βn

) is equal to :-

[11 Jan 2019 Shift 2]

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