JEE Main 11 Jan 2019 Shift 1 Solved Paper

Section: Physics

Question : 6 of 90

Marks: +1, -0

An amplitude modulated signal is given by V(t) = 10[1 + 0.3cos(2.2 × 104)]sin(5.5 × 105t). Here t is in seconds. The sideband frequencies (in kHz) are, [Given π = 22/7]

[11 Jan 2019 Shift 1]

1785 and 1715
892.5 and 857.5
89.25 and 85.75
178.5 smf 171.5

Validate

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