JEE Main 11 Jan 2019 Shift 1 Solved Paper

Section: Mathematics

Question : 46 of 90

Marks: +1, -0

A square is inscribed inthe circlex2+y2 – 6x + 8y – 103 = 0 with its sides parallelto the corrdinate axes. Then the distance of thevertex of this square which is nearest to theorigin is :-

[11 Jan 2019 Shift 1]

13
√137
6
√41

Validate

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