A wire, of length L( = 20 cm), is bent into a semi-circular arc. If the two equal halves, of the arc, were each to be uniformly charged with charges \pmQ|Q|=10^3\epsilon_0 Coulomb where \epsilon_0 is the permittivity (in SI units) of free space] the net electric field at the centre O of the semi-circular arc would be : [Main 11 Apr 2015]

Correct Answer is : (25×103N/C)∧i

(50\times10^3N\text{/}C)j^{∧}

(25\times10^3N\text{/}C)i^{∧}

(25\times10^3N\text{/}C)j^{∧}

(50\times10^3N\text{/}C)i^{∧}

JEE Main 11 April 2015 Paper

Section: Physics

Question : 14 of 90

Marks: +1, -0

A wire, of length L( = 20 cm), is bent into a semi-circular arc. If the two equal halves, of the arc, were each to be uniformly charged with charges ±Q|Q|=103ε0 Coulomb where ε0 is the permittivity (in SI units) of free space] the net electric field at the centre O of the semi-circular arc would be :

[Main 11 Apr 2015]

(50×103N/C)
∧
j
(25×103N/C)
∧
i
(25×103N/C)
∧
j
(50×103N/C)
∧
i

Validate

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