JEE Main 10 Jan 2019 Shift 2 Solved Paper

Section: Physics

Question : 8 of 90

Marks: +1, -0

At some location on earth the horizontal component of earth's magnetic field is 18 × 10–6 T. At this location, magnetic needle of length 0.12 m and pole strength 1.8 Am is suspended from its mid-point using a thread, it makes 45° angle with horizontalin equilibrium. To keep this needle horizontal, the vertical force that should be applied at one of its ends is :

[10 Jan 2019 Shift 2]

3.6 × 10–5 N
6.5 × 10–5 N
1.3 × 10–5 N
1.8 × 10–5 N

Validate

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