JEE Main 10 Jan 2019 Shift 2 Solved Paper

Section: Physics

Question : 6 of 90

Marks: +1, -0

A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11V is connected across it is :

[10 Jan 2019 Shift 2]

11 × 10–5 W
11 × 10–4 W
11 × 105 W
11 × 10–3 W

Validate

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