JEE Main 10 Jan 2019 Shift 2 Solved Paper

Section: Mathematics

Question : 37 of 90

Marks: +1, -0

If mean and standard deviation of 5 observations x1,x2,x3,x4,x5 are 10 and 3, respectively, then the variance of 6 observations x1,x2 , .... , x5 and –50 is equal to :

[10 Jan 2019 Shift 2]

582.5
507.5
586.5
509.5

Validate

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