JEE Main 10 Jan 2019 Shift 2 Solved Paper

Section: Mathematics

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Question : 35 of 90

Marks: +1, -0

The value of

π

2

∫

−

π

2

dx

[x]+[sinx]+4

, where [t] denotes the greatest integer less than or equalto t, is :

[10 Jan 2019 Shift 2]

1
12
(7π + 5)
3
10
(4π - 3)
1
12
(7π - 5)
3
20
(4π - 3)

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