JEE Main 10 Jan 2019 Shift 2 Solved Paper

Section: Physics

Question : 12 of 90

Marks: +1, -0

Condiser the nuclear fission
Ne20 → 2He4+C12
Given that the binding energy/nucleon of Ne20, He4 and C12 are, respectively, 8.03 MeV, 7.07 MeV and 7.86 MeV, identify the correct statement :

[10 Jan 2019 Shift 2]

8.3 MeV energy will be released
energy of 12.4 MeV will be supplied
energy of 11.9 MeV has to be supplied
energy of 3.6 MeV will be released

Validate

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