JEE Main 10 Jan 2019 Shift 1 Solved Paper

Section: Chemistry

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Question : 69 of 90

Marks: +1, -0

Hall-Heroult's process is given by "

[10 Jan 2019 Shift 1]

Cr2O3 + 2Al → Al2O3 + 2Cr
Cu2+ (aq.) + H2 (g) → Cu (s) + 2H+ (aq)
ZnO + C
Coke,1673K
→
Zn + CO
2Al2O3 + 3C → 4 Cl + 3CO2

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