JEE Main 10 Jan 2019 Shift 1 Solved Paper

Section: Mathematics
© examsiri.com
Question : 37 of 90
 
Marks: +1, -0
The equation of a tangent to the hyperbola 4x25y2 = 20 parallel to the line x – y = 2 is :
[10 Jan 2019 Shift 1]
Go to Question: