JEE Main 10 Jan 2019 Shift 1 Solved Paper

Section: Physics

Question : 22 of 90

Marks: +1, -0

A string of length 1 m and mass 5 g is fixed at both ends. The tension in the string is 8.0 N. The siring is set into vibration using an external vibrator of frequency 100 Hz. The separation between successive nodes on the string is close to :

[10 Jan 2019 Shift 1]

16.6 cm
20.0 cm
10.0 cm
33.3 cm

Validate

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