A submarine experience a pressure of 5.05\times 10^{6} P a at a depth of d_1 in a sea. When it goes further to a depth of .it experiences a pressure of 8.08\times 10^{6} P a .then d_1-d_2 is approximately(density of water=10^{3}{ k g} / m^{3} and acceleration due to gravity =10ms ^{-2} ): [10 Apr 2019 Shift 2]

JEE Main 10 Apr 2019 Paper 2 Solved Paper

Section: Physics

Question : 4 of 90

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A submarine experience a pressure of 5.05×106Pa at a depth of d1 in a sea. When it goes further to a depth of .it experiences a pressure of 8.08×106Pa .then d1−d2 is approximately(density of water=103

and acceleration due to gravity =10ms−2 ):

[10 Apr 2019 Shift 2]

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