JEE Main 10 Apr 2019 Paper 2 Solved Paper

Section: Physics

Question : 29 of 90

Marks: +1, -0

In a Young’s double slit experiment, the ratio of the slit’s width is 4:1 The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be:

[10 Apr 2019 Shift 2]

(√3+1)4:16
25:9
9:1
4:1

Validate

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