JEE Main 10 Apr 2019 Paper 2 Solved Paper

Section: Physics

Question : 25 of 90

Marks: +1, -0

The magnitude of the magnetic field at the centre of an equilateral triangular loop of side 1 m which is carrying a current of 10A is:{take µ0=4π×10−7NA−2} }

[10 Apr 2019 Shift 2]

18 µT
3 µT
1 µT
9 µT

Validate

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