If \\alpha and \\beta are roots of the quadratic equation x^{2}+\sin \\theta x-2 \sin \\theta=0, \\theta\in(0, \frac{\\pi}{2} ), then {\\alpha^{12}+\\beta^{12}}/{ (\\alpha^{-12}+\\beta^{-12} )(\\alpha-\\beta)^{24}} is equal to [10 Apr 2019 Shift 1]

Correct Answer is : 212(8+sinθ)12

{2^{6}}/{(8+\sin \\theta)^{12}}

{2^{12}}/{(8+\sin \\theta)^{12}}

{2^{12}}/{(8-\sin \\theta)^{6}}

{2^{12}}/{(4-\sin \\theta)^{6}}

JEE Main 10 Apr 2019 Paper 1 Solved Paper

Section: Mathematics

Question : 69 of 90

Marks: +1, -0

If α and β are roots of the quadratic equation x2+sin‌θ‌x−2‌sin‌θ=0,θ∈(0,

), then

α12+β12

(α−12+β−12)(α−β)24

is equal to

[10 Apr 2019 Shift 1]

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