The electric field of a plane electromagnetic wave is given by\overrightarrow{E}=E_{0} \stackrel{\^}{i} \cos (k z) \cos (\\omega t) The corresponding magnetic field B^{\to} is then givenby : [10 Apr 2019 Shift 1]

Correct Answer is : →B=E0C ^jsin(kz)sin(ωt)

\overrightarrow{B}= {E_{0}}/{C} \stackrel{\^}{k} \sin (k z) \cos (\\omega t)

\overrightarrow{B}= {E_{0}}/{C} {j} ^{\^}\sin (k z) \cos (\\omega t)

\overrightarrow{B}= {E_{0}}/{C} {j} ^{\^}\sin (k z) \sin(\\omega t)

\overrightarrow{B}= {E_{0}}/{C} \stackrel{\^}{k} \cos (k z) \sin (\\omega t)

JEE Main 10 Apr 2019 Paper 1 Solved Paper

Section: Physics

Question : 6 of 90

Marks: +1, -0

The electric field of a plane electromagnetic wave is given by

→

=E0

‌cos(kz)‌cos(ωt) The corresponding magnetic field

→

is then givenby :

[10 Apr 2019 Shift 1]

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