The area, enclosed by the curves y=\sin x+\cos x and y=|\cos x-\sin x| and the lines x=0, x=\frac{\\pi}{2}, is [1 Sep 2021 Shift 2]

Correct Answer is : 2√2(√2−1)

JEE Main 1-Sep-2021 Shift 2 Solved Paper

Section: Mathematics

Question : 71 of 90

Marks: +1, -0

The area, enclosed by the curves y=sin‌x+cos‌x and y=|cos‌x−sin‌x| and the lines x=0,x=

, is

[1 Sep 2021 Shift 2]

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