JEE Main 1-Sep-2021 Shift 2 Solved Paper

Given, b1=3b2
Here, b1 = width of the one of the two slit
and b2 = width of the other slit.
As we know that,
Intensity, I ∝(Amplitude)2
⇒

I1

I2

=(

b1

b2

)2
⇒

I1

I2

=(

3b2

b2

)2
As we know, the ratio of the minimum intensity to the maximumintensity in the interference pattern,

Imin

Imax

=(

√I1−√I2

√I1+√I2

)2
Substituting the values in the above equations, we get

Imin

Imax

=

(√9I2−√I2)2

(√9I2+√I2)2

=√(

3−1

3+1

)2

Imin

Imax

=

1

4

Comparing with,

Imin

Imax

=

x

4

The value of x = 1.