JEE Main 1-Sep-2021 Shift 2 Solved Paper

From the potential energy curve,
Umax=

1

2

kA2
10=

1

2

k(2)2
⇒ k = 5 N / m
The length of the simple pendulum, L = 4 m
Time period of spring,
T=2π√

k

m

Time period of simple pendulum,
T=2π√

I

g

The time period of simple pendulum is same as the time period ofthe spring oscillation.
⇒2π√

I

g

=2π√

k

m

Substituting the values in the above equations, we get
2π√

4

g

=2π√

5

5

g=4m∕s2
∴ The acceleration due to the gravity on the planet is 4m∕s2.