JEE Main 1-Sep-2021 Shift 2 Solved Paper

In the steady state, the inductor behaves as a conducting wire.So, the equivalent circuit becomes as shown below. Equivalent resistance of R1,R2 and R3 is given as,

1

R′

=

1

R1

+

1

R2

+

1

R3

1

R′

=

1

3

+

1

3

+

1

3

⇒ Req=1Ω
Now, the circuit becomes
Req=2+1=3Ω
Voltage, V = 30 V
Using the Ohm’s law,
V = IR
30 = I (3)
⇒ I = 10 A
∴ The steady state current is 10 A.