JEE Main 1-Feb-2024 Shift 2 Solved Paper

Section: Mathematics
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Question : 4 of 90
 
Marks: +1, -0
The value of
1
∫
0
(2x3−3x2−x+1)‌
1
3
‌dx
is equal to:
[1-Feb-2024 Shift 2]
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