Let S =\{z \in C: |z-1| = 1 and ( \sqrt{2} -1) (z+ \overline{z}) -i (z-\ov {z} ) = 2 {\sqrt2 \}. Let {\z}_1, {\z}_2\in S be such that { |z_1| }=\max _{{z \in S}} {|z|} and z_2=\min _{z \in S}|z|. Then {| \sqrt{2} z_1-z_2 |}^2 equals : [1-Feb-2024 Shift 1]

JEE Main 1-Feb-2024 Shift 1 Solved Paper

Section: Mathematics

Question : 6 of 90

Marks: +1, -0

Let S ={z∈C:|z−1|=1 and (√2−1)(z+z)−i(z−z)=2‌√2}. Let z1,z2∈S be such that |z1|=

max

z∈S

‌|z| and z2=

min

z∈S

|z|. Then |√2z1−z2|2 equals :

[1-Feb-2024 Shift 1]

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