JEE Main 1-Feb-2024 Shift 1 Solved Paper

Section: Mathematics

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Question : 4 of 90

Marks: +1, -0

If tan‌A=‌

1

√x(x2+x+1)

,tan‌B=‌

√x

√x2+x+1

and
tan‌C=(x−3+x−2+x−1)‌

1

2

,0<A,B,C<‌

π

2

, then A+B is equal to :

[1-Feb-2024 Shift 1]

C
π−C
2π−C
‌
π
2
−C

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