If 5 f(x)+4 f (\frac{1}{x}) =x^2-2, \forall x \neq 0 and y=9 x^2 f(x), then y is strictly increasing in : [1-Feb-2024 Shift 1]

Correct Answer is : (−1√5,0)∪(1√5,∞)

(0, {1}/{\sqrt{5}}) \cup ( {1}/{\sqrt{5}}, \infty)

(- {1}/{\sqrt{5}}, 0) \cup ( {1}/{\sqrt{5}}, \infty)

(- {1}/{\sqrt{5}}, 0) \cup (0, {1}/{\sqrt{5}})

(-\infty, {1}/{\sqrt{5}}) \cup (0, {1}/{\sqrt{5}})

JEE Main 1-Feb-2024 Shift 1 Solved Paper

Section: Mathematics

Question : 19 of 90

Marks: +1, -0

If 5f(x)+4f(‌

)=x2−2,∀x≠0 and y=9x2f(x), then y is strictly increasing in :

[1-Feb-2024 Shift 1]

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