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JEE Main 1-Feb-2024 Shift 1 Solved Paper

Section: Mathematics
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Question : 16 of 90
 
Marks: +1, -0
Let ‌
x2
a2
+‌
y2
b2
=1,a>b be an ellipse, whose eccentricity is ‌
1
√2
 and the length of the latus rectum is √14. Then the square of the eccentricity of ‌
x2
a2
−‌
y2
b2
=1 is :
[1-Feb-2024 Shift 1]
Validate
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