JEE Main 1-Feb-2024 Shift 1 Solved Paper

Section: Mathematics

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Question : 14 of 90

Marks: +1, -0

Let y=y(x) be the solution of the differential equation ‌

dy

dx

=2x(x+y)3−x(x+y)−1,y(0)=1.
Then, (‌

1

√2

+y(‌

1

√2

))2 equals :

[1-Feb-2024 Shift 1]

‌
4
4+√e
‌
3
3−√e
‌
2
1+√e
‌
1
2−√e

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