Impulse & Momentum

Section: Physics

Question : 2 of 16

Marks: +1, -0

A block of mass 5 kg moves along the x-direction subject to the force F=(−20x+10)N, with the value of x in metre. At time t=0 s, it is at rest at position x=1m. The position and momentum of the block at t=(π∕4) s are

[JEE Adv 2024 P1]

−0.5m,5‌kg‌m∕ s
0.5m,0‌kg‌m∕ s
0.5m,−5‌kg‌m∕ s
−1m,5‌kg‌m∕ s

Validate

Go to Question:

Prev Question

Next Question