The equilibrium constant for the following reaction is In^{2+} + Cu^{2+} → In + Cu^{\+} (at 298K) [Given E^\circ_{Cu^{2+}\/Cu^{\+}} = + 0.15V ; E^\circ_{In^{3+}\/In^{\+}} = -0.42V ; E^\circ_{In^{2+}\/In^{\+} = -0.40V] 10^{2x} The value of ' x ' is _______.

JEE Advanced Model Paper 9 with solutions for online practice

Question : 7 of 57

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The equilibrium constant for the following reaction is
In2+ + Cu2+ → In + Cu+ (at 298K)
[Given E°Cu2+∕Cu+ = + 0.15V ; E°In3+∕In+ = -0.42V ; E°In2+∕In+ = -0.40V] 102x
The value of ' x ' is _______.

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