∫ {e^\tan^{-1}x}/{1+x^2} [\sec^{-1}\sqrt{1+x^2} + \cos^{-1}(\frac{1-x^2}{1+x^2})] dx =

Correct Answer is : etan−1x(tan−1x)2 + c

e^{\tan^{-1}}x (\tan^{-1}x)^2 + c

e^{\tan^{-1}}x (\cot^{-1}x)^2 + c

e^{\tan^{-1}}x (\sin^{-1}x)^2 + c

e^{\tan^{-1}}x (\cos^{-1}x)^2 + c

JEE Advanced Model Paper 7 with solutions for online practice

Passage-3

If f(x) is differentiable then ∫ ex (f(x) + f'(x)) dx = ex f(x) + c . Using this result answer thefollowing

Question : 36 of 66

Marks: +1, -0

∫

etan−1x

1+x2

[sec−1√1+x2 + cos−1(

1−x2

1+x2

)] dx =

Go to Question:

Prev Question

Next Question