JEE Advanced Model Paper 7 with solutions for online practice

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Question : 25 of 66

Marks: +1, -0

If f(x) =

Lt

x→∞

An =

n

Σ

r=0

(tan

x

2r+1

+tan3

x

2r+1

)

1−tan2

x

2r+1

then

An =
sin
x
2n+1
cos
x
2n+1
cos
x
2n
An = tanx - tan
x
2n+1
Lt
x→0

f(x)−sinx
x3
=
2
3
Lt
x→∞

f(x)−sinx
x3
=
1
3

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