JEE Advanced Model Paper 7 with solutions for online practice

Equation of motion down the incline is given by mgsinα - (kx) mgcosα = ma ⇒ a = gsinα - (kx) gcosα
But , a =

dv

dt

= (

dv

dx

) (

dx

dt

) = v

dv

dx

∴ Vdv = (gsinα - kxgcosα) dx

v

∫

0

vdv =

x

∫

0

(gsinα - kxgcosα) dx ⇒

V2

2

= gxsinα -

kx2

2

gcosα
∴ V = √2gxsinα−kx2gcosα
Velocity again becomes zero, after x =

2

k

tanα