JEE Advanced Model Paper 6 with solutions for online practice

20 milli moles of NaOH = 20 milli moles of NaHSO3
= 40 milli equivalent of NaHSO3
∵ x grams of NaHSO3 = 40 meq (or) 0.04 equivalents
2x grams of NaHSO3 = 0.08 equivalents
Hence 0.08 = V × 0.1 × 6 (of K2Cr2O7)
∴ V =

0.08

0.6

L = 133.3 mL