JEE Advanced Model Paper 6 with solutions for online practice

Question : 37 of 60

Marks: +1, -0

COLUMN–I

COLUMN – II

A) cos

is the root of

P) 4x2 - 2x - 1 = 0

B) if cos p = tan q, cos q = tan r, cos r = tan p
then 1/2 sinp , 1/2 sinq , 1/2 sinr are the roots of

q) 4x2 + 2x - 1 = 0

C) cos

is the root of

r) 8x3−4x2 - 4x + 1 = 0

D) cos

is the root of

s) 16x5−20x3 + 5x = 0

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