JEE Advanced Model Paper 5 with solutions for online practice

Answer (A, B, D)
The slopes of tangent is 1, we have

dy

dx

=

1+x2

(1−x2)2

= 1
∴ x = 0 , ± √3
∴ The points are (0, 0) (√3,−

√3

2

) and (−√3,

√3

2

)
Equation of normal at (0, 0) is x + y = 0
Equation of normal at (√3,−

√3

2

) is x + y =

√3

2

Equation of normal at (−√3,

√3

2

) is x + y = -

√3

2