JEE Advanced Model Paper 4 with solutions for online practice

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Question : 32 of 54

Marks: +1, -0

0.17g AgN03 ( aq) mixed with 5.85g NaCl(aq) to form AgCl (white ppt)

0.1435g AgCI will be formed
0.585 g NaCl react with AgN03
5.7915 g NaCl will be left unreacted
1.435 g AgCl will be formed

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