JEE Advanced Model Paper 3 with solutions for online practice

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Question : 41 of 60
 
Marks: +1, -0
Let K be a positive real number and
A = [
2k−12√k2√k
2√k1−2k
−2√k2k−1
]
, B = [
02k−1√k
1−2k02√k
−√k−2√k0
]

If det (adJA) + det (adJB) = 106 , Then
the value of [
K
2
]
where [.] denotes greatest integer function
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