JEE Advanced Model Paper 20 with solutions for online practice

Given planes are x + y = 0, y + z = 0, z + x = 0; x + y + z = 2√6
Let OA be x + y = 0 or

x

−1

=

y

−1

=

z

1

..... (1)
Its opposite edge BC is

x

1

=

y

−1

=

z−2√6

0

Let l, m, n be the dc’s of line along shortest distance. Then

l

1

=

m

1

=

n

2

= √

l2+m2+n2

√6

∴ required distance =

1

√6

(0 - 0) +

1

√6

(0 - 0) +

2

√6

(2√6 - 0) =

2×2√6

√6