JEE Advanced Model Paper 20 with solutions for online practice

© examsiri.com
Question : 22 of 57
 
Marks: +1, -0
Given the point P(6, 10) and the ellipse x2+4y2 = 25
St-1 : The point P is nearest to the ellipse at (3, 2).
St-2 : Normal to the ellipse at (3, 2) is 8x – 3y = 18.
Go to Question: