JEE Advanced Model Paper 2 with solutions for online practice

The region bounded by given curves on the right side of x = 1 is shown

Thus, the required area
=

√2

∫

1

{x2−(2−x2)}dx +

2

∫

√2

{4 - x2} dx =

√2

∫

1

(2x2 - 2) dx +

2

∫

√2

(4 - x2) dx
= [2

x3

3

−2x]1√2 + [4x−

x3

3

]√22
= (

4√2

3

−2√2) = (

2

3

−2) + (8−

8

3

) - (4√2−

2√2

3

)
= (−4√2+

20

3

) = (

20−12√2

3

) sq units