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JEE Advanced Model Paper 2 with solutions for online practice

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Answer Q - 16 , Q - 17 and Q - 18 by appropriately matching the information given in the three columns of the following table.
Electron is given velocity according to column I any one of the electric fields of column II and any one of the electric field of column III is switched on. Neglect the gravitational field.
Column-I : Initial Velocity of electron Column-II : Intensity of electric field Column-III : Intensity of electric field
A)
→
V1
 = (V0
^
i
) at position (0, 0, 0) 		I)
−
E1
 =
x
^
i
x2+y2
 P)
−
E1
 = 2
^
i
B)
→
V2
 = (V0
^
j
) at position s 		II)
−
E2
 = 2
^
j
−
E2
 =
y
^
j
x2+y2
→
V3
 = (V0
^
k
) at any position
−
E3
 = 2
^
k
 R)
−
E3
 = 2
^
k
D)
→
V4
 = (V0
^
i
+V0
^
j
) at any position		 IV)
−
E4
 = 2
^
i
+2
^
j
−
E4
 = 2
^
i
−2
^
j
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Question : 18 of 54
 
Marks: +1, -0
In which case the particle may move in circular path (Assuming acceleratedcharge does not loose any energy
Validate
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