JEE Advanced Model Paper 2 with solutions for online practice

Given circuit is

The circuit equivalent to

Now, given VaC = 48 Vac
So, current through 8 Ω I1 resistor =

Vac

Rac

=

48

8

= 6 A
And current trough 24 Ω resistor I2 =

V

R

=

48

24

= 2 A
Hence, current flowing out of network
I1+I2 = 6 + 2 = 8A
∴ Current flowing through XY is 8A.

Now ,

1

Req

=

1

20

+

1

30

+

1

60

=

3+2+1

60

⇒ Req =

60

6

= 10 Ω

1

Req

=

1

24

+

1

8

=

1+3

24

⇒ Req =

24

4

= 6 Ω
So , RXY = 3 + 10 + 6 = 19 Ω
Hence , VXY = IRXY = 8 × 19 = 152 V