JEE Advanced Model Paper 19 with solutions for online practice

In Δle ABC , AB2 = AC2+BC2 - 2 AC . BC cos θ
AC2+BC2 is max → AB2 + 2 AC BC cos θ is max. But for allpositions of C, AB and O are constants. AC.BC maximum or

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AC.BC sin θ is max.
∴ AC2+BC2 max. implies Δ is max or

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h × AB is maximumor h is maximum → height is the diameter.
∴ AC = CB or Δle is isosceles