JEE Advanced Model Paper 19 with solutions for online practice

If the normal drawn is ⊥ o the line joining A(–1, –1) and B(2, 8). Tangent will be parallel to AB. If C (x1,y1) is that point then using leg range’s theorem to f(x) x3 on [-1 , 2]. f (x1) =

f(2)−f(−1)

2−(−1)

. We get x = - 1 or 1