Which carboxylic acid (A) , NE = 52g/eq , loses CO_2 when heated to given an acid (B) , NE = 60 g/eq. Where NE = \frac{\molecular \mass}{\Number \of \ionizable \H} )

Correct Answer is : A = CH2(COOH)2 ; B = CH3COOH

A = CH_2(COOH)_2 ; B = CH_3COOH

JEE Advanced Model Paper 18 with solutions for online practice

For Questions 35 & 36

The neutralization Equivalent is Eq.wt (

) of an acid as determined by titration withstandard NaOH . The number of ionisable (H) of an acid is the number of equivalentsper mole and is equal to

(Gemdicarboxyllic acids on heating loses CO2)

Question : 35 of 60

Marks: +1, -0

Which carboxylic acid (A) , NE = 52g/eq , loses CO2 when heated to given an acid
(B) , NE = 60 g/eq. Where NE =

molecular‌mass

Number‌of‌ionizable‌H

)

A = CH2(COOH)2 ; B = CH3COOH

Validate

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