JEE Advanced Model Paper 17 with solutions for online practice

x2 + (1 - 2a) x2 + 2x + (a2 - 5a + 6) = 0
⇒ a2 - (2x2 + 5) a + (x4+x2 + 2x + 6) = 0
⇒ a2 - [(x2 + 2x + 2) + (x2 - 2x + 3)]a + (x2 + 2x + 2) (x2 - 2x + 3) = 0
⇒ a = x2 + 2x + 2 ⇒ a ≥ 1 ..... (1)
on a = x2 - 2x + 3 ⇒ a ≥ 2 ..... (2)
From (1) and (2)
a ≥ 2