JEE Advanced Model Paper 17 with solutions for online practice
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Question : 40 of 60
Marks:
+1,
-0
Calculate ring strain energy (in KJ m o l − 1 ) of cyclopropane (g)
Given :
( Δ f H ) C O 2 ( g ) = - 390 KJ m o l − 1 , ( Δ f H ) H 2 O ( l ) = - 280 KJ m o l − 1 ( Δ comb H ) C 3 H 6 = - 2050 KJ m o l − 1 , ( Δ f H ) cycloprpane = 48 KJ m o l − 1
Given :
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