JEE Advanced Model Paper 17 with solutions for online practice

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Question : 2 of 60

Marks: +1, -0

A particle of mass m moves from rest along a straight line under the action of a force fvarying with time as f = f0 [1−(

t−T

T

)2] where f0 and T are positive constants. Then,

The speed of the particle after a time 2T is
4f0T
3m
After time interval of 3T, the particle starts moving backwards
Between time instants 0 and 2T, the acceleration first increases and then decreases
The particle stops at t = 3T

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